From 6fd763ff769931baad8460226a7e58378369aed5 Mon Sep 17 00:00:00 2001 From: Florian Fischer Date: Thu, 23 Nov 2023 15:47:41 +0100 Subject: improve DFD solution --- Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex | 11 ++++++----- 1 file changed, 6 insertions(+), 5 deletions(-) diff --git a/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex b/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex index c3fcbc19..4bd13ebf 100644 --- a/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex +++ b/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex @@ -5,23 +5,24 @@ Zeichne eine Datenflussdiagramm zu der von David beschriebenen Rechnung. \end{Aufg} \begin{Lsg} -\begin{tikzpicture} +\begin{tikzpicture}[func/.style={draw=black, rounded corners=2pt}] \node (f1) {3}; \node[right=of f1] (f2) {x}; -\node[below=of f2] (p) {PRODUKT}; +\node[func, below=of f2] (p) {PRODUKT}; \draw[-Triangle] (f1) -- (p); \draw[-Triangle] (f2) -- (p); \node[right=of f2] (s1) {x}; \node[right=of s1] (s2) {4}; -\node[below=of s1] (S1) {Summe}; +\node[func, right=of p] (S1) {SUMME}; \draw[-Triangle] (s1) -- (S1); \draw[-Triangle] (s2) -- (S1); -\node[below=of S1] (S2) {Summe}; +\node[func, below=of S1] (S2) {SUMME}; \draw[-Triangle] (p) -- (S2); \draw[-Triangle] (S1) -- (S2); -\draw[-Triangle] (S2) -- ($(S2) - (0, 0.3cm)$); +\draw[-Triangle] (S2) -- ($(S2) - (0, 0.5cm)$); \end{tikzpicture} + \BE{3} 1 pro Funktion und \BE{1} für eine richtige Form \end{Lsg} -- cgit v1.2.3