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authorFlorian Fischer <florian.fischer@muhq.space>2023-11-23 15:47:41 +0100
committerFlorian Fischer <florian.fischer@muhq.space>2023-11-23 15:47:41 +0100
commit6fd763ff769931baad8460226a7e58378369aed5 (patch)
treeca605ab90c47b9750ab98ab2cfe6ca3523eadd2e
parent7291702f8c31da0e8eca155f2869efeff3f99ee6 (diff)
downloadunterricht-6fd763ff769931baad8460226a7e58378369aed5.tar.gz
unterricht-6fd763ff769931baad8460226a7e58378369aed5.zip
improve DFD solution
-rw-r--r--Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex11
1 files changed, 6 insertions, 5 deletions
diff --git a/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex b/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex
index c3fcbc19..4bd13ebf 100644
--- a/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex
+++ b/Info/23_24/11/14/9B/Aufgaben/dfd_aus_term.tex
@@ -5,23 +5,24 @@ Zeichne eine Datenflussdiagramm zu der von David beschriebenen Rechnung.
\end{Aufg}
\begin{Lsg}
-\begin{tikzpicture}
+\begin{tikzpicture}[func/.style={draw=black, rounded corners=2pt}]
\node (f1) {3};
\node[right=of f1] (f2) {x};
-\node[below=of f2] (p) {PRODUKT};
+\node[func, below=of f2] (p) {PRODUKT};
\draw[-Triangle] (f1) -- (p);
\draw[-Triangle] (f2) -- (p);
\node[right=of f2] (s1) {x};
\node[right=of s1] (s2) {4};
-\node[below=of s1] (S1) {Summe};
+\node[func, right=of p] (S1) {SUMME};
\draw[-Triangle] (s1) -- (S1);
\draw[-Triangle] (s2) -- (S1);
-\node[below=of S1] (S2) {Summe};
+\node[func, below=of S1] (S2) {SUMME};
\draw[-Triangle] (p) -- (S2);
\draw[-Triangle] (S1) -- (S2);
-\draw[-Triangle] (S2) -- ($(S2) - (0, 0.3cm)$);
+\draw[-Triangle] (S2) -- ($(S2) - (0, 0.5cm)$);
\end{tikzpicture}
+
\BE{3} 1 pro Funktion und \BE{1} für eine richtige Form
\end{Lsg}