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authorFlorian Fischer <florian.fischer@muhq.space>2024-11-02 17:25:08 +0100
committerFlorian Fischer <florian.fischer@muhq.space>2024-11-02 17:25:08 +0100
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treefb1d65976010d70217bb4ebd5914c9315f0439fe /Mathe/9/2/1/Intro/slides.md
parent867416d0d7348e6dbe402ced303c053e7902cf50 (diff)
downloadunterricht-e99a58ee3789e1dfd8f7aeaba250e1e63c3be89c.tar.gz
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move quadratic function intro material into generic dir
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+---
+author: Florian Fischer
+theme: metropolis
+aspectratio: 169
+header-includes: |
+ \makeatletter
+ \beamer@ignorenonframefalse
+ \makeatother
+---
+
+
+##
+
+![](img/Copyrighted/escooter.png){.center}
+
+##
+
+![](img/Copyrighted/WDR_escooter_autobahn.png){.center}
+
+##
+
+\begin{center}
+\begin{tikzpicture}
+ \node[rotate=2] {\includegraphics[keepaspectratio, width=\textwidth]{img/Copyrighted/auto.png}};
+ \pause
+ \node[rotate=-3] {\includegraphics[keepaspectratio, width=\textwidth]{img/Copyrighted/mofa.png}};
+\end{tikzpicture}
+\end{center}
+
+## Faustregel
+
+Länge des Bremswegs in m $= (\frac{\text{Geschwindigkeit in km/h}}{10})^2$
+\vspace{0.2cm}
+
+\pause
+### Tatsächliche Bremswege
+
+> * $bw(45) = (\frac{45}{10})^2 = 20.25$ Meter
+> * $bw(120) = (\frac{120}{10})^2 = 144$ Meter
+
+## {.standout}
+
+Wie verändert sich der Bremsweg, wenn man die Geschwindigkeit verdoppelt?