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+\documentclass[a5paper]{handout}
+\csname endofdump\endcsname
+\usepackage{pgfplots}
+
+\renewcommand{\baselinestretch}{1.5} 
+\title{}
+\begin{document}
+\thispagestyle{empty}
+\makedate
+
+\begin{tabular}{p{0.6\textwidth} p{0.4\textwidth}}
+\vspace{-2.75cm}
+Graphen der Funktion $f:x\mapsto x^2$\solution{$+y_s$} \newline sind um \solution{$y_s$~~~} in y-Richtung verschoben. \newline
+Ihr Scheitelpunkt liegt bei \solution{$S(0|y_s)$} &
+\begin{tikzpicture}
+\begin{axis}[
+  x=0.5cm, y=0.5cm,
+  axis x line=center,
+  axis y line=center,
+  xtick={-2,...,2},
+  ytick={0,...,4},
+  xlabel={$x$},
+  ylabel={$y$},
+  xlabel style={below right},
+  ylabel style={above right},
+  ymin=-1.2, ymax=5.5,
+  xmin=-3, xmax=3,
+  grid=both,
+  unbounded coords=discard
+]
+  \addplot[domain=-2.3:2.3, samples=50, gray, thick] (\x, {\x^2});
+  \solution{\addplot[domain=-2.3:2.3, samples=50, orange, thick] (\x, {\x^2+1});}
+  \solution{\addplot[domain=-2.3:2.3, samples=50, magenta, thick] (\x, {\x^2-1});}
+\end{axis}
+\node[anchor=west] at (2.5, 1.9) {\scriptsize \textcolor{gray}{$\bm{f(x) = x^2}$}};
+\node[anchor=west] at (2.5, 0.9) {\scriptsize \textcolor{orange}{$\bm{f_2(x)=x^2+1}$}};
+\node[anchor=west] at (2.5, 1.4) {\scriptsize \textcolor{magenta}{$\bm{f_1(x)=x^2-1}$}};
+\end{tikzpicture}
+\\
+\end{tabular}
+
+\begin{tabular}{p{0.4\textwidth} p{0.6\textwidth}}
+\begin{tikzpicture}
+\begin{axis}[
+  x=0.5cm, y=0.5cm, 
+  axis x line=center,
+  axis y line=center,
+  xtick={-2,...,2},
+  ytick={0,...,4},
+  xlabel={$x$},
+  ylabel={$y$},
+  xlabel style={below right},
+  ylabel style={above right},
+  ymin=-1.2, ymax=5.5,
+  xmin=-3, xmax=3,
+  grid=both,
+  unbounded coords=discard
+]
+  \addplot[domain=-2.3:2.3, samples=50, gray, thick] (\x, {\x^2});
+  \solution{\addplot[domain=-2.3:2.3, samples=50, orange, thick] (\x, {(\x+1)^2});}
+  \solution{\addplot[domain=-2.3:2.3, samples=50, magenta, thick] (\x, {(\x-1)^2});}
+\end{axis}
+\node[anchor=west] at (-2.1, 2.8) {\scriptsize \textcolor{gray}{$\bm{f(x) = x^2}$}};
+\node[anchor=west] at (-2.1, 2.3) {\scriptsize \textcolor{orange}{$\bm{f_1(x)=(x+1)^2}$}};
+\node[anchor=west] at (-2.1, 1.8) {\scriptsize \textcolor{magenta}{$\bm{f_2(x)=(x-1)^2}$}};
+\end{tikzpicture}
+& \vspace{-2.75cm} Graphen der Funktion $f:x\mapsto (x\solution{-x_s~~~})^2$ sind um \solution{$x_s$~~~} in x-Richtung verschoben.
+Ihr Scheitelpunkt liegt bei \solution{$S(0|y_s)$} \\
+\end{tabular}
+
+\begin{merke}
+Die Darstellung einer quadratischen Funktion der Form
+{\setlength{\abovedisplayskip}{2pt}
+\setlength{\belowdisplayskip}{2pt}
+\[ f:x\mapsto \solution{a(x-x_s)^2+y_s} \]}
+nennt man \solution{Scheitelpunktform.} \\
+Ihr Scheitelpunkt $(x_s|y_s)$ kann vom Term direkt abgelesen werden.
+\end{merke}
+\end{document}